math和mathematics
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数学 mathematics
数学 mathematics, maths(BrE), math(AmE)被除数 dividend
除数 divisor 商 quotient 等于 equals, is equal to, is equivalent to 大于 is greater than
小于 is lesser than
大于等于 is equal or greater than
小于等于 is equal or lesser than
运算符 operator
数字 digit
数 number
自然数 natural number
公理 axiom
定理 theorem
计算 calculation
运算 operation
证明 prove
假设 hypothesis, hypotheses(pl.)
命题 proposition
算术 arithmetic
加 plus(prep.), add(v.), addition(n.)
被加数 augend, summand
加数 addend
和 sum
减 minus(prep.), subtract(v.), subtraction(n.)
被减数 minuend
减数 subtrahend
差 remainder
乘 times(prep.), m
Mathematics 1993 Paper 2
Mathematics HK CE Paper
Form 5
HKCEE 1993 Mathematics II
93 If f(x) = 102x, then f(4y) = 1. A. 104y . B. 102 + 4y . C. 108y . D. 40y . E. 402y .
93 2. If s = n2
[2a + (n 1)d], then d =
A. 2(s an)n(n 1) . B. 2(s an)(n 1) .
C. sn(n 1) . D. as na(n 1) . E.
4(s an)
n(n 1)
.
93 Simplify (x2 3x + 1)(x2 +3x + 1). 3. A. x4 + 1 B. x4 x2 + 1 C. x4 + x2 + 1
D. x4 3x2 23x 1
E. x4 + 3x3 23x2 +3x 1
93 a4. a
b
+
aa
b
.
A. 1a
b
B.
a 2ab b
a b
93-CE-MATHS II C. b a
2a
D. b 2ab aa b
E.
a ba b
93 If 3x2 + ax 5 (bx 1)(2 x) 3, 5.
Mathematics 1993 Paper 2
Mathematics HK CE Paper
Form 5
HKCEE 1993 Mathematics II
93 If f(x) = 102x, then f(4y) = 1. A. 104y . B. 102 + 4y . C. 108y . D. 40y . E. 402y .
93 2. If s = n2
[2a + (n 1)d], then d =
A. 2(s an)n(n 1) . B. 2(s an)(n 1) .
C. sn(n 1) . D. as na(n 1) . E.
4(s an)
n(n 1)
.
93 Simplify (x2 3x + 1)(x2 +3x + 1). 3. A. x4 + 1 B. x4 x2 + 1 C. x4 + x2 + 1
D. x4 3x2 23x 1
E. x4 + 3x3 23x2 +3x 1
93 a4. a
b
+
aa
b
.
A. 1a
b
B.
a 2ab b
a b
93-CE-MATHS II C. b a
2a
D. b 2ab aa b
E.
a ba b
93 If 3x2 + ax 5 (bx 1)(2 x) 3, 5.
Welcome to 7 th Grade Math
Welcome to 7 th Grade Math
Welcome to 7th Grade MathTeacher: Miss Zurich
Welcome to 7 th Grade Math
Agenda
Welcome to 7 th Grade Math
About the Teacher Taught at WAMS since January 2002 Graduated from King’s College, Wilkes-Barre, PA B.S. Mathematics B.A. Computers and Information Systems Currently I am pursuing a M.A. at FDU in Instructional Technology
Welcome to 7 th Grade Math
7th Grade MathPhilosophy McDougal Littell Middle School Math, Course 3, teaches the skills and concepts of Pre-Algebra and Basic Mathematics th
Welcome to 7 th Grade Math
Welcome to 7 th Grade Math
Welcome to 7th Grade MathTeacher: Miss Zurich
Welcome to 7 th Grade Math
Agenda
Welcome to 7 th Grade Math
About the Teacher Taught at WAMS since January 2002 Graduated from King’s College, Wilkes-Barre, PA B.S. Mathematics B.A. Computers and Information Systems Currently I am pursuing a M.A. at FDU in Instructional Technology
Welcome to 7 th Grade Math
7th Grade MathPhilosophy McDougal Littell Middle School Math, Course 3, teaches the skills and concepts of Pre-Algebra and Basic Mathematics th
3-Math Preliminary1
第一章 算法分析的数学基础
生成函数(母函数)
在进行计数分析时,常常会遇到递推方程,形如:
an=cn-1*an-1 + cn-2*an-2 + … + cr*ar (cr≠0) 求解时有时需要使用生成函数的方法。 e.g. Fibonacci数列:满足关系an=an-1+an-2 (该类数有很多好的性质) 普通与指数生成函数的定义:
设{a0,a1,a2,…,an,…}是某一数域 (e.g. 有理数,实数,复数)上的数的序列, {μ0(x), μ1(x), μ2(x), … ,μn(x), …}
是同一数域上相互独立的函数序列,则称函数 F(x)=a0μ0(x)+ a1μ1(x)+ a2μ2(x)+ … + anμn(x)+ … 是序列{ a0,a1,a2,…,an,…}的普通生成函数 (普母函数);称函数G(x) =
a0μ0(x)/0! + a1μ1(x)/1! + a2μ2(x)/2! + … +anμn(x)/n! + …是序列{a0,a1,…,a2,…}的指数生成函数, (指母函数,和式形状类似于e的展开形式) 相互独立(independent)的函数序列: 设{μ0(x), μ1(x), μ2(x), … ,μn(x),
Problem-based Learning in Mathematics
Problem-Based Learning (PBL) describes a learning environment where problems drive the learning. That is, learning begins with a problem to be solved, and the problem is posed is such a way that students need to gain new knowledge before they can solve the
Problem-based Learning in Mathematics
Kyeong Ha RohApril 2003
Problem-Based Learning (PBL) describes a learning environment where problems drive the learning. That is, learning begins with a problem to be solved, and the problem is posed is such a way that students need to g
Problem-based Learning in Mathematics
Problem-Based Learning (PBL) describes a learning environment where problems drive the learning. That is, learning begins with a problem to be solved, and the problem is posed is such a way that students need to gain new knowledge before they can solve the
Problem-based Learning in Mathematics
Kyeong Ha RohApril 2003
Problem-Based Learning (PBL) describes a learning environment where problems drive the learning. That is, learning begins with a problem to be solved, and the problem is posed is such a way that students need to g
css-applied-mathematics2-2013
applied mathematics
FEDERAL PUBLIC SERVICE COMMISSION
COMPETITIVE EXAMINATION FOR RECRUITMENT TO POSTS IN BS-17 UNDER THE FEDERAL GOVERNMENT, 2013
TIME ALLOWED: THREE HOURS MAXIMUM MARKS: 100
NOTE: (i) Candidate must write Q. No. in the Answer Book in accordance with Q. No. in the Q. Paper.
(ii) Attempt FIVE questions in all by selecting TWO questions from SECTION-A and ONE
question from SECTION-B and TWO questions from SECTION-C ALL questions carry EQUAL marks.
(iii) Extra attempt of any question or any part of the att
css-applied-mathematics2-2013
applied mathematics
FEDERAL PUBLIC SERVICE COMMISSION
COMPETITIVE EXAMINATION FOR RECRUITMENT TO POSTS IN BS-17 UNDER THE FEDERAL GOVERNMENT, 2013
TIME ALLOWED: THREE HOURS MAXIMUM MARKS: 100
NOTE: (i) Candidate must write Q. No. in the Answer Book in accordance with Q. No. in the Q. Paper.
(ii) Attempt FIVE questions in all by selecting TWO questions from SECTION-A and ONE
question from SECTION-B and TWO questions from SECTION-C ALL questions carry EQUAL marks.
(iii) Extra attempt of any question or any part of the att