IPv4 ClassicalSubnettingPractice_KEY
更新时间:2023-05-14 01:09:01 阅读量: 实用文档 文档下载
Classical Subnetting Practice
KEY
Part 1
Given each network address, and for the subnet required provide the following: Subnet Address:
Subnet Mask: (both dotted-decimal and slash notation):
Host Range:
Broadcast Address:
Default Gateway:
Note: If the question refershosts, subnets sizes must be as small as possible but still satisfy the required number.
1. 10.0.0.0
a. Create 117 subnets and 255 hosts per subnet
b. Provide answers for Subnet 2
Subnet Address:10.0.4.0
Subnet Mask: /23 or 255.255.254.0
Host Range: 10.0.4.1 – 10.0.5.254
Broadcast Address: 10.0.5.255
Default Gateway: 10.0.5.254
2. 172.31.0.0
a. Create 63 subnets with least 127 hosts
b. Provide answers for 2rd subnet
Subnet Address:172.31.1.0
Subnet Mask: /24 or 255.255.255.0
Host Range: 172.31.1.1 – 172.3131.254
Broadcast Address: 172.31.1.255
Default Gateway: 172.31.1.254
3. 10.0.0.0
a. Create 120 subnets
b. Provide answers for Subnet 4
Subnet Address:10.8.0.0
Subnet Mask: /15 or 255.254.0.0
Host Range: 10.8.1.1 – 10.9.255.254
Broadcast Address: 10.9.255.255
Default Gateway: 10.9.255.254
NETE1200 2017/18 Subnetting Practice 2
4. 192.168.0.0
a. 7 subnets and 31 hosts per
b. Provide answers for 4nd subnet
Not Doable
- Need 6 host bits (25-2 = 30)
- Only 2 subnet bits availab;e
- 22 = 4 – only 4 subnets can be created
5. 172.18.0.0
a. 195 hosts per subnet and 131 subnets
b. Provide answers for 5th subnet
Subnet Address:17.18.4.0
Subnet Mask: /24 or 255.255.255.0
Host Range: 172.18.4.1 – 172.18.4.254
Broadcast Address: 172.18.4.255
Default Gateway: 172.18.4.255
Part 2
Given each IPv4 address, provide the following:
Subnet Address:
Subnet Mask:
Host Range:
Address Type: host, network, broadcast, default gateway
1. 19
2.168.111.111/29
Subnet Address: 192.168.111.104
Subnet Mask: 255.255.255.248
Host Range:192.168.111.105 – 192.168.111.110
Address Type: Broadcast Address
2. 172.27.27.159/27
Subnet Address: 172.27.27.128
Subnet Mask: 255.255.255.224
Host Range:172.27.27.129 – 172.27.27.128
Address Type: Broadcast Address
NETE1200 2017/18 Subnetting Practice 3 3. 10.185.194.224/28
Subnet Address: 10.185.195.224
Subnet Mask: 255.255.255.240
Host Range:10.185.194.225 – 10.185.194.254
Address Type: Subnet Address
4. 192.168.64.62/30
Subnet Address: 192.168.64.60
Subnet Mask: 255.255.255.252
Host Range:192.168.64.61 – 192.168.64.62
Address Type: Host Address
5. 172.22.222.0/18
Subnet Address: 172.22.192.0
Subnet Mask: 255.255.192.0
Host Range:172.22.192.1 – 172.22.254.254
Address Type: Host Address
6. 172.22.224.0/19
Subnet Address: 172.22.224.0
Subnet Mask: 255.255.224.0
Host Range:172.22.224.1 – 172.22.254.254
Address Type: Subnet Address
7. 10.200.187.254/23
Subnet Address: 10.200.186.0
Subnet Mask: 255.255.254.0
Host Range:10.200.186.1 – 10.200.187.254
Address Type: Host Address (Default Gateway)
8. 10.255.255.126/25
Subnet Address: 10.255.255.0
Subnet Mask: 255.255.255.128
Host Range:10.255.255.1 – 10.255.255.126
Address Type: Host Address (Default Gateway)
NETE1200 2017/18 Subnetting Practice 4 Part 3
Identify whether the following pairs of addresses are on the same network/subnet.
1. 19
2.168.1.62/28
192.168.1.64/28
Different:
192.168.1.62/28 is on Subnet 192.168.1.48
192.168.1.64 is Subnet Address of next subnet
2. 172.26.20
3.1/23
172.26.204.1/23
Different:
172.26.203.1 is on Subnet 172.16.202.0
172.16.204.1 is on Subnet 172.16.204.0
3. 192.168.1.6/29
192.168.1.9/30
Different
To be on same subnet they must share same mask
4. 10.133.31.254/19
10.133.32.1/19
Different
10.133.21.254/19 is on Subnet 10.133.0.0
10.133.32.1/19 is on Subnet 10.133.32.0
5. 172.18.175.254/20
172.18.161.1/20
Same
They bare both on Subnet 172.18.160.0
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