KM, kcat, and kcat KM
更新时间:2023-09-04 16:46:01 阅读量: 教育文库 文档下载
max 是指 最大反应速度。当 底物浓度 足够大时,体系中 酶的活性中心达到饱和状态,其反应速度达到最大。 由此可见,最大反应速度 max 随 酶浓度的变化而变化。 kcat 指反应常数 ( catalytic constant ), kcat 可以由 这个公式计算得到:
kcat = max/[E]
[E] 指 酶浓度,由此可以说, kcat 表示了每单位时间内(秒)每摩尔的酶(或者说每摩尔的活性中心)能够把多少摩尔的底物转化成产物。
Km 俗称 米氏常数,以浓度做单位,米氏常数定义为 反应速度 达到 最大反应速度一半时 的底物浓度。 Km 可以反映出酶与底物的亲和力,Km越低,亲和力越大。
kcat/Km 称为 催化效率,常常以此来比较 不同的酶而同一底物, 或者 不同底物而同一种酶。
KM, kcat, and kcat /KM
KM - The Michaelis constant, KM, is often associated with the affinity of the enzyme for substrate, but this is not always correct. A more accurate statement is that, for reactions obeying Michaelis-Menten kinetics, KM is a measure of the substrate concentration required for effective catalysis to occur. That is, an enzyme with a high KM requires a higher substrate concentration to achieve a given reaction velocity than an enzyme with a low KM. lists values of KM, kcat, and kcat/KM
for selected enzymes.
kcat - The Michaelis-Menten equation, V = Vmax[S]/(KM + [S]), can be rewritten as V = kcat[E]t[S] / ( KM + [S])
where Vmax = kcat[E]t. kcat incorporates the rate constants for all the reactions between ES and E + P in a multistep enzymatic process. For a two-step reaction, kcat = k2. For more complex reactions, kcat depends on which steps in the process are rate-limiting. kcat gives a direct measure of the catalytic production of product under optimum
conditions (saturated enzyme). The units of kcat are seconds-1. The reciprocal of kcat can be thought of as the time required by an enzyme molecule to "turn over" one substrate molecule. Alternatively, kcat measures the number of substrate molecules
turned over per enzyme molecule per second. Thus, kcat is sometimes called the turnover number. Some typical turnover numbers are shown in , as well.
kcat/KM - This ratio is often thought of as a measure of enzyme efficiency. Either a large value of kcat (rapid turnover) or a small value of KM (high affinity for substrate) makes kcat/KM large.
When [S] << KM (dilute solution), equation 11.27 becomes V (kcat/KM)[E][S]
Here, kcat/KM behaves as a second-order rate constant for the reaction between substrate and free enzyme. This ratio is important, for it shows what the enzyme and substrate can accomplish when abundant enzyme sites are available, and it allows direct comparison of the effectiveness of an enzyme toward different substrates. When an
enzyme has a choice of two substrates, A or B, present at equal, dilute concentrations,
shows that when an enzyme has different substrates on which it can work, the range of efficiencies may vary considerably. Note that for chymotrypsin the kcat/KM ratio
varies 1-million fold.
As a second-order rate constant, kcat/KM has a maximum possible value, which is determined by the frequency with which enzyme and substrate molecules can collide. A reaction which attains such a velocity is said to be "diffusion-limited" because every
encounter leads to reaction. If every collision results in formation of an enzyme-substrate complex, diffusion theory predicts that kcat/KM will attain a value of about 108 to 109 (mol/L)-1s-1. The enzymes carbonic anhydrase, fumarase, and triose phosphate isomerase actually approach this limit.
正在阅读:
人教版小学品德与社会六年级上册《第三单元 腾飞的祖国 3 告别贫困奔小康》教学设计 - 1603-16
计算机网络习题110-12
品味亲恩作文800字06-27
舞蹈兴趣小组活动小结07-07
对当前行政执法活动中存在问题的对策与思考06-09
《白鹅》教学设计10-25
贵州省人事厅省卫生厅关于印发《贵州省破07-09
计算机网络认识实习报告10-23
- exercise2
- 铅锌矿详查地质设计 - 图文
- 厨余垃圾、餐厨垃圾堆肥系统设计方案
- 陈明珠开题报告
- 化工原理精选例题
- 政府形象宣传册营销案例
- 小学一至三年级语文阅读专项练习题
- 2014.民诉 期末考试 复习题
- 巅峰智业 - 做好顶层设计对建设城市的重要意义
- (三起)冀教版三年级英语上册Unit4 Lesson24练习题及答案
- 2017年实心轮胎现状及发展趋势分析(目录)
- 基于GIS的农用地定级技术研究定稿
- 2017-2022年中国医疗保健市场调查与市场前景预测报告(目录) - 图文
- 作业
- OFDM技术仿真(MATLAB代码) - 图文
- Android工程师笔试题及答案
- 生命密码联合密码
- 空间地上权若干法律问题探究
- 江苏学业水平测试《机械基础》模拟试题
- 选课走班实施方案
- kcat
- KM
- 道路货物运输经营申请表
- 建筑工程施工资料表格填写说明_secret
- 2014-2019年中国汽车门锁市场深度调查与投资前景调研报告
- 田径运动会裁判员学习田径规则及注意事项
- 沉积岩
- 查处非法营运基本规范
- 初三化学第一单元物质的变化复习资料
- 罗兰贝格-移动行业渠道管理
- 学校创建平安校园工作领导小组的组成及职责分工
- 热控词汇英汉对照
- 2020年专业技术人员继续教育在线作业及测试(公需科目)试题答案
- 检验科室内室间质控员工作记录本
- 招聘启事格式范文
- 高校学生学籍管理系统的构建
- 大学生饮食与营养健康
- 初、中级无损检测技术资格人员-超声检测考题汇编(一)
- (农大2016年)大学英语Ⅲ在线作业1,2
- 微机原理习题答案8章
- 第3章 酶动力学
- 2017年自贡市公需科目《大数据时代的互联网信息安全》考试题及答案