潭浩强C语言答案

第一章

1.6 main()

{int a,b,c,max;

printf(\ scanf(\ max=a;

if(max

printf(\2.10 9,11,9,10 2.12

(1)24 (2)10 (3)60 (4)0 (5)0 (6)0

第三章

3.4 main() COMPUTER, COM 3.6

a=3 b=7/

x=8.5 y=71.82/ c1=A c2=a/ 3.7

10 20Aa1.5 -3.75 +1.4,67.8/ (空3)10(空3)20Aa1.5(空1)-3.75(空}

第二章

2.3

(1)(10)10=(12)8=(a)16 (2)(32)10=(40)8=(20)16 (3)(75)10=(113)8=(4b)16

(4)(-617)10=(176627)8=(fd97)16 (5)(-111)10=(177621)8=(ff91)16 (6)(2483)10=(4663)8=(963)16

(7)(-28654)10=(110022)8=(9012)16 (8)(21003)10=(51013)8=(520b)16 2.6

aabb (8)cc (8)abc (7)AN 2.7 main()

{char c1='C',c2='h',c3='i',c4='n',c5='a'; c1+=4, c2+=4, c3+=4, c4+=4, c5+=4;

printf(\c5); } 2.8 main() {int c1,c2; c1=97;c2=98;

printf(\ %c\} 2.9 (1)=2.5 (2)=3.5

{int a,b,c; long int u,n; float x,y,z; char c1,c2; a=3;b=4;c=5;

x=1.2;y=2.4;z=-3.6; u=51274;n=128765; c1='a';c2='b'; printf(\ printf(\ b=- c=-\\n\

printf(\x,y,z);

printf(\ y+z=%5.2f z+x=%5.2f\\n\

printf(\ n=%9ld\\n\

printf(\;

printf(\; } 3.5 57 5 7

67.856400,-789.123962 67.856400,-789.123962 67.86

-789.12,67.856400,-789.123962,67.856400,-789.123962

6.785640e+001,-7.89e+002 A,65,101,41

1234567,4553207,d687 65535,177777,ffff,-1

1)(随意输入一个数），67.8回车 3.8 main()

{float pi,h,r,l,s,sq,sv,sz; pi=3.1415926;

printf(\ scanf(\ l=2*pi*r; s=r*r*pi; sq=4*pi*r*r;

sv=4.0/3.0*pi*r*r*r; sz=pi*r*r*h;

printf(\ printf(\ printf(\ printf(\ printf(\} 3.9 main() {float c,f;

scanf(\ c=(5.0/9.0)*(f-32); printf(\} 3.10

#include\main()

{char c1,c2;

scanf(\ putchar(c1); putchar(c2); printf(\

printf(\

1

}

第四章

4.3

(1)0 (2)1 (3)1 (4)0 (5)1 4.4 main() {int a,b,c;

scanf(\ if(a

printf(\ else

printf(\ else if(a

printf(\ else

printf(\}

main()

{int a,b,c,temp,max;

scanf(\ temp=(a>b)?a:b;

max=(c>temp)?c:temp; printf(\} 4.5 main() {int x,y;

scanf(\ if(x<1)y=x;

else if(x<10)y=2*x-1; else y=3*x-11; printf(\} 4.6 main()

{int score,temp,logic; char grade; logic=1; while(logic)

{scanf(\

if(score>=0&&score<=100)logic=0;

}

if(score==100) temp=9; else

temp=(score-score)/10; switch(temp)

{case 9:grade='A';break; case 8:grade='B';break; case 7:grade='C';break; case 6:grade='D';break; case 5: case 4: case 3: case 2: case 1:

case 0:grade='E'; }

printf\e); } 4.7 main()

{long int num; int

indiv,ten,hundred,thousand,ten_thousand,place;

scanf(\ if(num>9999) place=5; else if(num>999) place=4; else if(num>99) place=3; else if(num>9) place=2; else place=1;

printf(\ ten_thousand=num/10000;

thousand=(num-ten_thousand*10000)/1000;

hundred=(num-ten_thousand*10000-thousand*1000)/100;

ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10;

indiv=num-ten_thousand*10000-thousand*1000-hundred*100-ten*10; switch(place) {case

5:printf(\ousand,thousand,hundred,ten,indiv);

printf(\,hundred,thousand,ten_thousand); break; case

4:printf(%undred,ten,indiv);

printf(\dred,thousand); break; case

3:printf(\div);

printf(\d);

break; case

2:printf(\

printf(\ break;

case 1:printf(\ printf(\ } } 4.8 main() {long i; float

bonus,bon1,bon2,bon4,bon6,bon10; bon1=100000*0.1;

bon2=bon1+100000*0.075; bon4=bon2+200000*0.05; bon6=bon4+200000*0.03; bon10=bon6+400000*0.015; scanf(\

if(i<=1e5)bonus=i*0.1; else

if(i<=2e5)bonus=bon1+(i-100000)*0.0

2

75; else

if(i<=4e5)bonus=bon2+(i-200000)*0.05; else

if(i<=6e5)bonus=bon4+(i-400000)*0.03; else

if(i<=1e6)bonus=bon6+(i-600000)*0.015;

else bonus=bon10+(i-1000000)*0.01; printf(\}

main() {long i; float

bonus,bon1,bon2,bon4,bon6,bon10; int branch;

bon1=100000*0.1;

bon2=bon1+100000*0.075; bon4=bon2+200000*0.05; bon6=bon4+200000*0.03; bon10=bon6+400000*0.015; scanf(\ branch=i/100000;

if(branch>10)branch=10; switch(branch)

{case 0:bonus=i*0.1;break; case

1:bonus=bon1+(i-100000)*0.075;break;

case 2: case

3:bonus=bon2+(i-200000)*0.05;break; case 4: case

5:bonus=bon4+(i-400000)*0.03;break; case 6: case 7 case 8: case

9:bonus=bon6+(i-600000)*0.015;break; case

10:bonus=bon10+(i-1000000)*0.01; }

printf(\

} 4.9 main()

{int t,a,b,c,d;

scanf(\;

if(a>b){t=a;a=b;b=t;} if(a>c){t=a;a=c;c=t;} if(a>d){t=a;a=d;d=t;} if(b>c){t=b;b=c;c=t;} if(b>d){t=b;b=d;d=t;} if(c>d){t=c;c=d;d=t;}

printf(\ %d %d %d\\n\; } 4.10 main() {int h=10;

float x,y,x0=2,y0=2,d1,d2,d3,d4; scanf(\

d1=(x-x0)*(x-x0)+(y-y0)*(y-y0); d2=(x-x0)*(x-x0)+(y+y0)*(y+y0); d3=(x+x0)*(x+x0)+(y-y0)*(y-y0); d4=(x+x0)*(x+x0)+(y+y0)*(y+y0);

if(d1>1&&d2>1&&d3>1&&d4>1)h=0;

printf(\}

第五章 循环控制

5.1 main()

{int a,b,num1,num2,temp;

scanf(\

if(num1

b=temp;}

printf(\

printf(\} 5.2

#include\main() {char c;

int letters=0,space=0,digit=0,other=0; while((c=getchar())!='\\n')

{if(c>='a'&&c<='z'||c>='A'&&c<='Z') letters++;

else if(c==' ')space++;

else if(c>='0'&&c<='9')digit++; else other++; }

printf(\%d\\nother=%d\\n\her); } 5.3 main()

{int a,n,count=1,sn=0,tn=0; scanf(\ while(count<=n) {tn+=a; sn+=tn; a*=10; ++count; }

printf(\} 5.4 main()

{float n,s=0,t=1;

for(n=1;n<=20;n++) {t*=n; s+=t; }

printf(\} 5.5

3

main()

{int N1=100,N2=50,N3=10; float k;

float s1=0,s2=0,s3=0;

for(k=1;k<=N1;k++)s1+=k; for(k=1;k<=N2;k++)s2+=k*k; for(k=1;k<=N3;k++)s3+=1/k; printf(\} 5.6 main() {int i,j,k,n;

for(n=100;n<1000;n++) {i=n/100; j=n/10-i*10; k=n;

if(i*100+j*10+k==i*i*i+j*j*j+k*k*k) printf(\ } } 5.7

#define M 1000 main()

{int k0,k1,k2,k3,k4,k5,k6,k7,k8,k9; int i,j,n,s;

for(j=2;j<=M;j++) {n=0; s=j;

for(i=1;i

{case 1:k0=i;break; case 2:k1=i;break; case 3:k2=i;break; case 4:k3=i;break; case 5:k4=i;break; case 6:k5=i;break; case 7:k6=i;break; case 8:k7=i;break; case 9:k8=i;break; case 10:k9=i;break; }

} } if(s==0)

{printf(\

if(n>1)printf(\ if(n>2)printf(\ if(n>3)printf(\ if(n>4)printf(\ if(n>5)printf(\ if(n>6)printf(\ if(n>7)printf(\ if(n>8)printf(\ if(n>9)printf(\ } } }

main()

{static int k[10]; int i,j,n,s;

for(j=2;j<=1000;j++) {n=-1; s=j;

for(i=1;i

{printf(\ for(i=0;i

{int n,t,number=20; float a=2;b=1;s=0;

for(n=1;n<=number;n++) {s=s+a/b;

t=a,a=a+b,b=t; }

printf(\} 5.9 main()

{float sn=100.0,hn=sn/2; int n;

for(n=2;n<=10;n++) {sn=sn+2*hn; hn=hn/2; }

printf(\ printf(\} 5.10 main()

{int day,x1,x2; day=9; x2=1;

while(day>0) {x1=(x2+1)*2; x2=x1; day--; }

printf(\} 5.11

#include\main()

{float a,xn0,xn1; scanf(\ xn0=a/2;

xn1=(xn0+a/xn0)/2; do

{xn0=xn1;

xn1=(xn0+a/xn0)/2; }

while(fabs(xn0-xn1)>=1e-5);

printf(\); } 5.12

4

#include\main()

{float x,x0,f,f1; x=1.5; do

{x0=x;

f=((2*x0-4)*x0+3)*x0-6; f1=(6*x0-8)*x0+3; x=x0-f/f1; }

while(fabs(x-x0)>=1e-5); printf(\} 5.13

#include\main()

{float x0,x1,x2,fx0,fx1,fx2; do

{scanf(\ fx1=x1*((2*x1-4)*x1+3)-6; fx2=x2*((2*x2-4)*x2+3)-6; }

while(fx1*fx2>0); do

{x0=(x1+x2)/2;

fx0=x0*((2*x0-4)*x0+3)-6; if((fx0*fx1)<0) {x2=x0; fx2=fx0; } else

{x1=x0; fx1=fx0; } }

while(fabs(fx0)>=1e-5); printf(\} 5.14 main() {int i,j,k;

for(i=0;i<=3;i++)

{for(j=0;j<=2-i;j++) printf(\

for(k=0;k<=2*i;k++)

printf(\ printf(\ }

for(i=0;i<=2;i++) {for(j=0;j<=i;j++) printf(\

for(k=0;k<=4-2*i;k++) printf(\ printf(\ } } 5.15 main() {char i,j,k;

for(i='x';i<='z';i++) for(j='x';j<='z';j++) {if(i!=j)

for(k='x';k<='z';k++) {if(i!=k&&j!=k)

{if(i!='x'&&k!='x'&&k!='z')

printf(\ } } } }

第六章

6.1

#include #define N 101 main()

{ int i,j,line,a[N];

for (i=2;i

{if(a[i]!=0 && a[j]!=0) if (a[j]%a[i]==0) a[j]=0; } printf(\

for (i=2,line=0;i

{ printf(\ line++; } if(line==10)

{ printf(\ line=0; } } } 6.2

#define N 10 main()

{int i,j,min,temp,a[N]; for(i=0;i

for(j=i+1;j

if(a[min]>a[j])min=j; temp=a[i]; a[i]=a[min]; a[min]=temp; }

for(i=0;i

{float a[3][3],sum; int i,j;

for(i=0;i<3;i++) for(j=0;j<3;j++)

{scanf(\ a[i][j]=sum; }

for(i=0;i<3;i++) sum=sum+a[i][i]; printf(\} 6.4 main() {int

a[11]={1,4,6,9,13,16,19,28,40,100}; int temp1,temp2,number, end,i,j; scanf(\ end=a[9];

if(number>end) a[10]=number; else

{for(i=0;i<10;i++)

5

本文来源：https://www.bwwdw.com/article/fnnd.html