典型c++源代码

1：#include \

#include \main() {

printf(\); printf(\); printf(\); printf(\); printf(\); }

2：#include \

#include \main() {

int x,y,z,t;

scanf(\ if (x>y)

{t=x;x=y;y=t;} /*交换x,y的值*/ if(x>z)

{t=z;z=x;x=t;} /*交换x,z的值*/ if(y>z)

{t=y;y=z;z=t;} /*交换z,y的值*/

printf(\ }

3：#include \

#include \main() {

double i;

double bonus1,bonus2,bonus4,bonus6,bonus10,bonus; scanf(\ bonus1=100000*0.1;

bonus2=bonus1+100000*0.75;

bonus4=bonus2+200000*0.5; bonus6=bonus4+200000*0.3; bonus10=bonus6+400000*0.15; if(i<=100000) bonus=i*0.1;

else if(i<=200000)

bonus=bonus1+(i-100000)*0.075; else if(i<=400000)

bonus=bonus2+(i-200000)*0.05; else if(i<=600000)

bonus=bonus4+(i-400000)*0.03; else if(i<=1000000)

bonus=bonus6+(i-600000)*0.015; else

bonus=bonus10+(i-1000000)*0.01; printf(\}

4：#include \

#include \main() {

int day,month,year,sum,leap;

printf(\ scanf(\

switch(month) /*先计算某月以前月份的总天数*/ {

case 1:sum=0;break; case 2:sum=31;break; case 3:sum=59;break; case 4:sum=90;break; case 5:sum=120;break; case 6:sum=151;break; case 7:sum=181;break; case 8:sum=212;break; case 9:sum=243;break; case 10:sum=273;break; case 11:sum=304;break; case 12:sum=334;break;

default:printf(\ }

sum=sum+day; /*再加上某天的天数*/

if(year@0==0||(year%4==0&&year0!=0)) /*判断是不是闰年*/ leap=1; else

leap=0;

if(leap==1&&month>2) /*如果是闰年且月份大于2,总天数应该加一天*/ sum++;

printf(\ }

5：#include \

#include \main() {

int i,j,k,n;

printf(\ for(n=100;n<1000;n++) {

i=n/100;/*分解出百位*/ j=n/10;/*分解出十位*/ k=n;/*分解出个位*/

if(i*100+j*10+k==i*i*i+j*j*j+k*k*k) printf(\ } }

6：#include \

main() {

long f1,f2; int i; f1=f2=1;

for(i=1;i<=20;i++) {

printf(\

if(i%2==0) printf(\控制输出，每行四个*/ f1=f1+f2; /*前两个月加起来赋值给第三个月*/ f2=f1+f2; /*前两个月加起来赋值给第三个月*/ } }

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