Oracle.1Z0-051.175q

OCP 11g 051题库

1Z0-051 Oracle Database: SQL Fundamentals I

QUESTION 1

View the Exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS, and TIMES

tables.

The PROD_ID column is the foreign key in the SALES table, which references the PRODUCTS table.

Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the

CUSTOMERS and TIMES tables, respectively.

Evaluate the following CREATE TABLE command:

CREATE TABLE new_sales(prod_id, cust_id, order_date DEFAULT SYSDATE)

AS

SELECT prod_id, cust_id, time_id

FROM sales;

Which statement is true regarding the above command?

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A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.

B. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified columns would be passed to

C. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clau

D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the specified columns would be passe

Answer: B

QUESTION 2

View the Exhibit to examine the description for the SALES table.

Which views can have all DML operations performed on it? (Choose all that apply.)

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A. CREATE VIEW v3

AS SELECT * FROM SALES

WHERE cust_id = 2034

WITH CHECK OPTION;

B. CREATE VIEW v1

AS SELECT * FROM SALES

WHERE time_id <= SYSDATE - 2*365

WITH CHECK OPTION;

C. CREATE VIEW v2

AS SELECT prod_id, cust_id, time_id FROM SALES WHERE time_id <= SYSDATE - 2*365

WITH CHECK OPTION;

D. CREATE VIEW v4

AS SELECT prod_id, cust_id, SUM(quantity_sold) FROM SALES

WHERE time_id <= SYSDATE - 2*365

GROUP BY prod_id, cust_id

WITH CHECK OPTION;

Answer: AB

QUESTION 3

You need to extract details of those products in the SALES table where the PROD_ID column contains

the string '_D123'.

Which WHERE clause could be used in the SELECT statement to get the required output?

A. WHERE prod_id LIKE '%_D123%' ESCAPE '_'

B. WHERE prod_id LIKE '%\_D123%' ESCAPE '\'

C. WHERE prod_id LIKE '%_D123%' ESCAPE '%_'

D. WHERE prod_id LIKE '%\_D123%' ESCAPE '\_'

Answer: B

QUESTION 4 Which two statements are true regarding single row functions? (Choose two.)

A. They a ccept only a single argument.

B. They c an be nested only to two levels.

C. Arguments can only be column values or constants.

D. They a lways return a single result row for every row of a queried table.

E. They c an return a data type value different from the one that is referenced.

Answer: DE

QUESTION 5

Which SQL statements would display the value 1890.55 as $1,890.55? (Choose three .)

A. SELECT TO_CHAR(1890.55,'$0G000D00')

FROM DUAL;

B. SELECT TO_CHAR(1890.55,'$9,999V99')

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FROM DUAL;

C. SELECT TO_CHAR(1890.55,'$99,999D99')

FROM DUAL;

D. SELECT TO_CHAR(1890.55,'$99G999D00')

FROM DUAL;

E. SELECT TO_CHAR(1890.55,'$99G999D99')

FROM DUAL;

Answer: ADE

QUESTION 6

Examine the structure of the SHIPMENTS table:

name Null Type

PO_ID NOT NULL NUMBER(3)

PO_DATE NOT NULL DATE

SHIPMENT_DATE NOT NULL DATE

SHIPMENT_MODE VARCHAR2(30)

SHIPMENT_COST NUMBER(8,2)

You want to generate a report that displays the PO_ID and the penalty amount to be paid if the

SHIPMENT_DATE is later than one month from the PO_DATE. The penalty is $20 per day.

Evaluate the following two queries:

SQL> SELECT po_id, CASE

WHEN MONTHS_BETWEEN (shipment_date,po_date)>1 THEN

TO_CHAR((shipment_date - po_date) * 20) ELSE 'No Penalty' END PENALTY

FROM shipments;

SQL>SELECT po_id, DECODE

(MONTHS_BETWEEN (po_date,shipment_date)>1,

TO_CHAR((shipment_date - po_date) * 20), 'No Penalty') PENALTY

FROM shipments;

Which statement is true regarding the above commands?

A. Both execute successfully and give correct results.

B. Only the first query executes successfully but gives a wrong result.

C. Only the first query executes successfully and gives the correct result.

D. Only the second query executes successfully but gives a wrong result.

E. Only the second query executes successfully and gives the correct result.

Answer: C

QUESTION 7

Which two statements are true regarding the USING and ON clauses in table joins? (Choose two.)

A. Both USING and ON clauses can be used for equijoins and nonequijoins.

B. A maximum of one pair of columns can be joined between two tables using the ON clause.

C. The ON clause can be used to join tables on columns that have different names but compatible data types.

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D. The WHERE clause can be used to apply additional conditions in SELECT statements containing the ON or the USING clause.

Answer: CD

QUESTION 8

View the Exhibit and examine the structure of the CUSTOMERS table.

Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)

A. listing of customers who do not have a credit limit and were born before 1980

B. finding the number of customers, in each city, whose marital status is 'married'

C. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'

D. listing of those customers whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'

E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers

Answer: DE

QUESTION 9 Which statement is true regarding the INTERSECT operator?

A. It ignores NULL values.

B. Reversing the order of the intersected tables alters the result.

C. The names of columns in all SELECT statements must be identical.

D. The number of columns and data types must be identical for all SELECT statements in the query.

Answer: D

QUESTION 10

View the Exhibit; e xamine the structure of the PROMOTIONS table.

Each promotion has a duration of at least seven days .

Your manager has asked you to generate a report, which provides the weekly cost for each promotion

done to l date.

Which query would achieve the required result?

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A. SELECT promo_name, promo_cost/promo_end_date-promo_begin_date/7 FROM promotions;

B. SELECT promo_name,(promo_cost/promo_end_date-promo_begin_date)/7 FROM promotions;

C. SELECT promo_name, promo_cost/(promo_end_date-promo_begin_date/7) FROM promotions;

D. SELECT promo_name, promo_cost/((promo_end_date-promo_begin_date)/7) FROM promotions;

Answer: D

QUESTION 11

View the Exhibit and examine the structure of the PRODUCTS table.

All products have a list price.

You issue the following command to display the total price of each product after a discount of 25% and a tax

of 15% are applied on it. Freight charges of $100 have to be applied to all the products.

SQL>SELECT prod_name, prod_list_price -(prod_list_price*(25/100))

+(prod_list_price -(prod_list_price*(25/100))*(15/100))+100

AS "TOTAL PRICE"

FROM products;

What would be the outcome if all the parenthese s are removed from the above statement?

A. It produces a syntax error.

B. The result remains unchanged.

C. The total price value would be lower than the correct value.

D. The total price value would be higher than the correct value.

Answer: B

QUESTION 12

You need to produce a report where each customer's credit limit has been incremented by $1000. In the

output, t he customer's last name should have the heading Name and the incremented credit limit should

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be labeled New Credit Limit. The column headings should have only the first letter of each word in

uppercase .

Which statement would accomplish this requirement?

A. SELECT cust_last_name Name, cust_credit_limit + 1000

"New Credit Limit"

FROM customers;

B. SELECT cust_last_name AS Name, cust_credit_limit + 1000

AS New Credit Limit

FROM customers;

C. SELECT cust_last_name AS "Name", cust_credit_limit + 1000

AS "New Credit Limit"

FROM customers;

D. SELECT INITCAP(cust_last_name) "Name", cust_credit_limit + 1000 INITCAP("NEW CREDIT LIMIT")

FROM customers;

Answer: C

QUESTION 13

View the Exhibit and examine the structure of the PRODUCTS table.

You need to generate a report in the following format:

CATEGORIES

5MP Digital Photo Camera's category is Photo

Y Box's category is Electronics

Envoy Ambassador's category is Hardware

Which two queries would give the required output? (Choose two.)

A. SELECT prod_name q'''s category is ' prod_category CATEGORIES FROM products;

B. SELECT prod_name q'['s ]'category is ' prod_category CATEGORIES FROM products;

C. SELECT prod_name q'\'s\' ' category is ' prod_category CATEGORIES FROM products;

D. SELECT prod_name q'<'s >' 'category is ' prod_category CATEGORIES FROM products;

Answer: CD

QUESTION 14

Using the CUSTOMERS table, you need to generate a report that shows 50% of each credit amount

in each income level. The report should NOT show any repeated credit amounts in each income level.

Which query would give the required result?

A. SELECT cust_income_level, DISTINCT cust_credit_limit * 0.50 AS "50% Credit Limit"

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FROM customers;

B. SELECT DISTINCT cust_income_level, DISTINCT cust_credit_limit * 0.50 AS "50% Credit Limit"

FROM customers;

C. SELECT DISTINCT cust_income_level ' ' cust_credit_limit * 0.50 AS "50% Credit Limit"

FROM customers;

D. SELECT cust_income_level ' ' cust_credit_limit * 0.50 AS "50% Credit Limit" FROM customers;

Answer: C

QUESTION 15

View the Exhibit and examine the data in the CUSTOMERS table.

Evaluate the following query:

SQL> SELECT cust_name AS "NAME", cust_credit_limit/2 AS MIDPOINT,MIDPOINT+100 AS "MAX

LOWER LIMIT"

FROM customers;

The above query produces an error on execution.

What is the reason for the error?

A. An alias cannot be used in an expression.

B. The a lias NAME should not be enclosed with in double quotation marks .

C. The MIDPOINT+100 expression gives an error because CUST_CREDIT_LIMIT contains NULL values.

D. The a lias MIDPOINT should be enclosed with in double quotation marks for the CUST_CREDIT_LIMIT/2 expression .

Answer: A

QUESTION 16

Evaluate the following query:

SQL> SELECT promo_name q'{'s start date was }' promo_begin_date

AS "Promotion Launches"

FROM promotions;

What would be the outcome of the above query?

A. It produces an error because flower braces have been used.

B. It produces an error because the data types are not matching.

C. It executes successfully and introduces an 's at the end of each promo_name in the output.

D. It executes successfully and displays the literal " {'s start date was } " for each row in the output.

Answer: C

QUESTION 17

View the E xhibit and examine the data in the EMPLOYEES table.

You want to generate a report showing the total compensation paid to each employee to date.

You issue the following query:

SQL>SELECT ename ' joined on ' hiredate

', the total compensation paid is '

TO_CHAR(ROUND(ROUND(SYSDATE-hiredate)/365) * sal + comm)

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"COMPENSATION UNTIL DATE"

FROM employees;

What is the outcome?

A. It generates an error because the alias is not valid.

B. It executes successfully and gives the correct output.

C. It executes successfully but does not give the correct output.

D. It generates an error because the usage of the ROUND function in the expression is not valid.

E. It generates an error because the concatenation operator can be used to combine only two items.

Answer: C

QUESTION 18

Examine the structure of the PROMOTIONS table:

name Null Type

PROMO_ID NOT NULL NUMBER(6)

PROMO_NAME NOT NULL VARCHAR2(30)

PROMO_CATEGORY NOT NULL VARCHAR2(30)

PROMO_COST NOT NULL NUMBER(10,2)

The management wants to see a report of unique promotion costs in each promotion category.

Which query would achieve the required result?

A. SELECT DISTINCT promo_cost, promo_category FROM promotions;

B. SELECT promo_category, DISTINCT promo_cost FROM promotions;

C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;

D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;

Answer: D

QUESTION 19

Evaluate the following query:

SELECT INTERVAL '300' MONTH,

INTERVAL '54-2' YEAR TO MONTH,

INTERVAL '11:12:10.1234567' HOUR TO SECOND

FROM dual;

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What is the correct output of the above query?

A. +25-00 , +54-02, +00 11:12:10.123457

B. +00-300, +54-02, +00 11:12:10.123457

C. +25-00 , +00-650, +00 11:12:10.123457

D. +00-300 , +00-650, +00 11:12:10.123457

Answer: A

QUESTION 20

Which three statements are true regarding the data types in Oracle Database 10g/11g? (Choose three.)

A. Only one LONG column can be used per table.

B. A TIMESTAMP data type column stores only time values with fractional seconds.

C. The BLOB data type column is used to store binary data in an operating system file.

D. The minimum column width that can be specified for a VARCHAR2 data type column is one.

E. The value for a CHAR data type column is blank-padded to the maximum defined column width.

Answer: ADE

QUESTION 21

Examine the description of the EMP_DETAILS table given below:

name NULL TYPE

EMP_ID NOT NULL NUMBER

EMP_NAME NOT NULL VARCHAR2 (40)

EMP_IMAGE LONG

Which two statements are true regarding SQL statements that can be executed on the EMP_DETAIL table?

(Choose two.)

A. An EMP_IMAGE column can be included in the GROUP BY clause.

B. An EMP_IMAGE column cannot be included in the ORDER BY clause.

C. You cannot add a new column to the table with LONG as the data type.

D. You can alter the table to include the NOT NULL constraint on the EMP_IMAGE column.

Answer: BC

QUESTION 22 You need to create a table for a banking application. One of the columns in the table has the following

requirements:

1) You want a column in the table to store the duration of the credit period.

2) The data in the column should be stored in a format such that it can be easily added and subtracted with

DATE data type without using conversion functions.

3) The maximum period of the credit provision in the application is 30 days.

4) The interest has to be calculated for the number of days an individual has taken a credit for.

Which data type would you use for such a column in the table?

A. DATE

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B. NUMBER

C. TIMESTAMP

D. INTERVAL DAY TO SECOND

E. INTERVAL YEAR TO MONTH

Answer: D

QUESTION 23

Examine the structure proposed for the TRANSACTIONS table:

name Null Type

TRANS_ID NOT NULL NUMBER(6)

CUST_NAME NOT NULL VARCHAR2(20)

CUST_STATUS NOT NULL CHAR

TRANS_DATE NOT NULL DATE

TRANS_VALIDITY VARCHAR2

CUST_CREDIT_LIMIT NUMBER

Which statements are true regarding the creation and storage of data in the above table structure? (Choose

all that apply.)

A. The CUST_STATUS column would give an error.

B. The TRANS_VALIDITY column would give an error.

C. The CUST_STATUS column would store exactly one character.

D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.

E. The TRANS_VALIDITY column would have a maximum size of one character.

F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes, seconds, and fractions of seconds.

Answer: BC

QUESTION 24

Examine the structure proposed for the TRANSACTIONS table:

name Null Type

TRANS_ID NOT NULL NUMBER(6)

CUST_NAME NOT NULL VARCHAR2(20)

CUST_STATUS NOT NULL VARCHAR2

TRANS_DATE NOT NULL DATE

TRANS_VALIDITY INTERVAL DAY TO SECOND

CUST_CREDIT_VALUE NUMBER(10)

Which two statements are true regarding the storage of data in the above table structure? (Choose two.)

A. The TRANS_DATE column would allow storage of dates only in the dd-mon-yyyy format.

B. The CUST_CREDIT_VALUE column would allow storage of positive and negative integers.

C. The TRANS_VALIDITY column would allow storage of a time interval in days, hours, minutes, and seconds.

D. The CUST_STATUS column would allow storage of data up to the maximum VARCHAR2 size of 4,000 characters.

Answer: BC

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QUESTION 25

Resume (character large object [CLOB] data type), which contains the resume submitted by the

employee

Which is the correct syntax to create this table?

A. CREATE TABLE EMP_1

(emp_id NUMBER(4),

emp_name VARCHAR2(25),

start_date DATE,

e_status VARCHAR2(10) DEFAULT 'ACTIVE',

resume CLOB(200));

B. CREATE TABLE 1_EMP

(emp_id NUMBER(4),

emp_name VARCHAR2(25),

start_date DATE, emp_status VARCHAR2(10) DEFAULT 'ACTIVE',

resume CLOB);

C. CREATE TABLE EMP_1

(emp_id NUMBER(4),

emp_name VARCHAR2(25),

start_date DATE,

emp_status VARCHAR2(10) DEFAULT "ACTIVE",

resume CLOB);

D. CREATE TABLE EMP_1

(emp_id NUMBER,

emp_name VARCHAR2(25),

start_date DATE,

emp_status VARCHAR2(10) DEFAULT 'ACTIVE',

resume CLOB);

Answer: D

QUESTION 26

Which is the valid CREATE TABLE statement?

A. CREATE TABLE emp9$# (emp_no NUMBER (4));

B. CREATE TABLE 9emp$# (emp_no NUMBER(4));

C. CREATE TABLE emp*123 (emp_no NUMBER(4));

D. CREATE TABLE emp9$# (emp_no NUMBER(4), date DATE);

Answer: A

QUESTION 27

Which two statements are true regarding tables? (Choose two.)

A. A table name can be of any length.

B. A table can have any number of columns.

C. A column that has a DEFAULT value cannot store null values.

D. A table and a view can have the same name in the same schema.

E. A table and a synonym can have the same name in the same schema.

F. The same table name can be used in different schemas in the same database.

Answer: EF

QUESTION 28

Which two statements are true regarding constraints? (Choose two.)

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A. A foreign key cannot contain NULL values.

B. A column with the UNIQUE constraint can contain NULL values.

C. A constraint is enforced only for the INSERT operation on a table.

D. A constraint can be disabled even if the constraint column contains data.

E. All constraints can be defined at the column level as well as the table level.

Answer: BD

QUESTION 29

Which two statements are true regarding constraints? (Choose two.)

A. A foreign key cannot contain NULL values.

B. The column with a UNIQUE constraint can store NULLS .

C. A constraint is enforced only for an INSERT operation on a table.

D. You can have more than one column in a table as part of a primary key.

Answer: BD

QUESTION 30

Evaluate the following CREATE TABLE commands:

CREATE TABLE orders

(ord_no NUMBER(2) CONSTRAINT ord_pk PRIMARY KEY,

ord_date DATE,

cust_id NUMBER(4));

CREATE TABLE ord_items

(ord_no NUMBER(2),

item_no NUMBER(3),

qty NUMBER(3) CHECK (qty BETWEEN 100 AND 200),

expiry_date date CHECK (expiry_date > SYSDATE), CONSTRAINT it_pk PRIMARY KEY (ord_no,item_no),

CONSTRAINT ord_fk FOREIGN KEY(ord_no) REFERENCES orders(ord_no));

The above command fails when executed. What could be the reason?

A. SYSDATE cannot be used with the CHECK constraint.

B. The BETWEEN clause cannot be used for the CHECK constraint.

C. The CHECK constraint cannot be placed on columns having the DATE data type.

D. ORD_NO and ITEM_NO cannot be used as a composite primary key because ORD_NO is also the FOREIGN KEY.

Answer: A

QUESTION 31

Evaluate the following SQL commands:

SQL>CREATE SEQUENCE ord_seq

INCREMENT BY 10

START WITH 120

MAXVALUE 9999

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NOCYCLE;

SQL>CREATE TABLE ord_items

(ord_no NUMBER(4)DEFAULT ord_seq.NEXTVAL NOT NULL,

item_no NUMBER(3),

qty NUMBER(3) CHECK (qty BETWEEN 100 AND 200),

expiry_date date CHECK (expiry_date > SYSDATE),

CONSTRAINT it_pk PRIMARY KEY (ord_no,item_no),

CONSTRAINT ord_fk FOREIGN KEY(ord_no) REFERENCES orders(ord_no));

The command to create a table fails. Identify the reason for the SQL statement failure? (Choose all that

apply.)

A. You cannot use SYSDATE in the condition of a CHECK constraint.

B. You cannot use the BETWEEN clause in the condition of a CHECK constraint.

C. You cannot use the NEXTVAL sequence value as a DEFAULT value for a column.

D. You cannot use ORD_NO and ITEM_NO columns as a composite primary key because ORD_NO is also the FOREIGN KEY.

Answer: AC

QUESTION 32

Which CREATE TABLE statement is valid?

A. CREATE TABLE ord_details

(ord_no NUMBER(2) PRIMARY KEY,

item_no NUMBER(3) PRIMARY KEY,

ord_date DATE NOT NULL);

B. CREATE TABLE ord_details

(ord_no NUMBER(2) UNIQUE, NOT NULL,

item_no NUMBER(3),

ord_date DATE DEFAULT SYSDATE NOT NULL);

C. CREATE TABLE ord_details

(ord_no NUMBER(2) ,

item_no NUMBER(3),

ord_date DATE DEFAULT NOT NULL,

CONSTRAINT ord_uq UNIQUE (ord_no),

CONSTRAINT ord_pk PRIMARY KEY (ord_no));

D. CREATE TABLE ord_details

(ord_no NUMBER(2),

item_no NUMBER(3),

ord_date DATE DEFAULT SYSDATE NOT NULL,

CONSTRAINT ord_pk PRIMARY KEY (ord_no, item_no));

Answer: D

QUESTION 33

You want to create an ORD_DETAIL table to store details for an order placed having the following

business requirement:

1) The order ID will be unique and cannot have null values.

2) The order date cannot have null values and the default should be the current date.

3) The order amount should not be less than 50.

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4) The order status will have values either shipped or not shipped.

5) The order payment mode should be cheque, credit card, or cash on delivery (COD).

Which is the valid DDL statement for creating the ORD_DETAIL table?

A. CREATE TABLE ord_details

(ord_id NUMBER(2) CONSTRAINT ord_id_nn NOT NULL,

ord_date DATE DEFAULT SYSDATE NOT NULL,

ord_amount NUMBER(5, 2) CONSTRAINT ord_amount_min

CHECK (ord_amount > 50),

ord_status VARCHAR2(15) CONSTRAINT ord_status_chk

CHECK (ord_status IN ('Shipped', 'Not Shipped')),

ord_pay_mode VARCHAR2(15) CONSTRAINT ord_pay_chk

CHECK (ord_pay_mode IN ('Cheque', 'Credit Card',

'Cash On Delivery')));

B. CREATE TABLE ord_details

(ord_id NUMBER(2) CONSTRAINT ord_id_uk UNIQUE NOT NULL,

ord_date DATE DEFAULT SYSDATE NOT NULL,

ord_amount NUMBER(5, 2) CONSTRAINT ord_amount_min

CHECK (ord_amount > 50),

ord_status VARCHAR2(15) CONSTRAINT ord_status_chk

CHECK (ord_status IN ('Shipped', 'Not Shipped')),

ord_pay_mode VARCHAR2(15) CONSTRAINT ord_pay_chk

CHECK (ord_pay_mode IN ('Cheque', 'Credit Card',

'Cash On Delivery')));

C. CREATE TABLE ord_details

(ord_id NUMBER(2) CONSTRAINT ord_id_pk PRIMARY KEY,

ord_date DATE DEFAULT SYSDATE NOT NULL,

ord_amount NUMBER(5, 2) CONSTRAINT ord_amount_min

CHECK (ord_amount >= 50),

ord_status VARCHAR2(15) CONSTRAINT ord_status_chk

CHECK (ord_status IN ('Shipped', 'Not Shipped')),

ord_pay_mode VARCHAR2(15) CONSTRAINT ord_pay_chk

CHECK (ord_pay_mode IN ('Cheque', 'Credit Card',

'Cash On Delivery')));

D. CREATE TABLE ord_details

(ord_id NUMBER(2),

ord_date DATE NOT NULL DEFAULT SYSDATE,

ord_amount NUMBER(5, 2) CONSTRAINT ord_amount_min

CHECK (ord_amount >= 50),

ord_status VARCHAR2(15) CONSTRAINT ord_status_chk

CHECK (ord_status IN ('Shipped', 'Not Shipped')),

ord_pay_mode VARCHAR2(15) CONSTRAINT ord_pay_chk

CHECK (ord_pay_mode IN ('Cheque', 'Credit Card',

'Cash On Delivery')));

Answer: C

QUESTION 34

You created an ORDERS table with the following description:

name Null Type

ORD_ID NOT NULL NUMBER(2)

CUST_ID NOT NULL NUMBER(3)

ORD_DATE NOT NULL DATE

ORD_AMOUNT NOT NULL NUMBER (10,2)

You inserted some rows in the table. After some time, you want to alter the table by creating the PRIMARY

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KEY constraint on the ORD_ID column. Which statement is true in this scenario?

A. You cannot have two constraints on one column.

B. You cannot add a primary key constraint if data exists in the column.

C. The primary key constraint can be created only at the time of table creation .

D. You can add the primary key constraint even if data exists, provided that there are no duplicate values.

Answer: D

QUESTION 35

Which two statements are true regarding constraints? (Choose two.)

A. A table can have only one primary key and one foreign key.

B. A table can have only one primary key but multiple foreign keys.

C. Only the primary key can be defined at the column and table levels.

D. The foreign key and parent table primary key must have the same name.

E. Both primary key and foreign key constraints can be defined at both column and table levels.

Answer: BE

QUESTION 36

Examine the following SQL commands:

SQL>CREATE TABLE products (

prod_id NUMBER(3) CONSTRAINT p_ck CHECK (prod_id > 0),

prod_name CHAR(30),

prod_qty NUMBER(6),

CONSTRAINT p_name NOT NULL,

CONSTRAINT prod_pk PRIMARY KEY (prod_id));

SQL>CREATE TABLE warehouse (

warehouse_id NUMBER(4),

roomno NUMBER(10) CONSTRAINT r_id CHECK(roomno BETWEEN 101 AND 200),

location VARCHAR2(25),

prod_id NUMBER(3),

CONSTRAINT wr_pr_pk PRIMARY KEY (warehouse_id,prod_id),

CONSTRAINT prod_fk FOREIGN KEY (prod_id) REFERENCES products(prod_id));

Which statement is true regarding the execution of the above SQL commands?

A. Both commands execute successfully.

B. The first CREATE TABLE command generates an error because the NULL constraint is not valid.

C. The second CREATE TABLE command generates an error because the CHECK constraint is not valid.

D. The first CREATE TABLE command generates an error because CHECK and PRIMARY KEY constraints cannot be used for the saE. The first CREATE TABLE command generates an error because the column PROD_ID cannot be used in the PRIMARY KEY and FO

Answer: B

QUESTION 37

You issued the following command to drop the PRODUCTS table:

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SQL> DROP TABLE products;

What is the implication of this command? (Choose all that apply.)

A. All data along with the table structure is deleted.

B. The pending transaction in the session is committed.

C. All indexes on the table will remain but they are invalidated.

D. All views and synonyms will remain but they are invalidated.

E. All data in the table are deleted but the table structure will remain.

Answer: ABD

QUESTION 38

Which two statements are true regarding views? (Choose two.)

A. A simple view in which column aliases have been used cannot be updated.

B. Rows cannot be deleted through a view if the view definition contains the DISTINCT keyword.

C. Rows added through a view are deleted from the table automatically when the view is dropped.

D. The OR REPLACE option is used to change the definition of an existing view without dropping and re-creating it.

E. The WITH CHECK OPTION constraint can be used in a view definition to restrict the columns displayed through the view.

Answer: BD

QUESTION 39

Evaluate the following command:

CREATE TABLE employees

(employee_id NUMBER(2) PRIMARY KEY,

last_name VARCHAR2(25) NOT NULL,

department_id NUMBER(2)NOT NULL,

job_id VARCHAR2(8),

salary NUMBER(10,2));

You issue the following command to create a view that displays the IDs and last names of the sales staff in

the organization:

CREATE OR REPLACE VIEW sales_staff_vu AS4 ? 4;

SELECT employee_id, last_name,job_id4 ? 4;

FROM employees4 ? 4;

WHERE job_id LIKE 'SA_%'4 ? 4; WITH CHECK OPTION;

Which two statements are true regarding the above view? (Choose two.)

A. It allows you to insert rows into the EMPLOYEES table .

B. It allows you to delete details of the existing sales staff from the EMPLOYEES table.

C. It allows you to update job IDs of the existing sales staff to any other job ID in the EMPLOYEES table.

D. It allows you to insert IDs, last names, and job IDs of the sales staff from the view if it is used in multitable INSERT statements.

Answer: BD

OCP 11g 051题库

QUESTION 40

View the Exhibit to examine the description for the SALES and PRODUCTS tables.

You want to create a SALE_PROD view by executing the following SQL statement:

CREATE VIEW sale_prod

AS SELECT p.prod_id, cust_id, SUM(quantity_sold) "Quantity" , SUM(prod_list_price) "Price"

FROM products p, sales s

WHERE p.prod_id=s.prod_id

GROUP BY p.prod_id, cust_id;

Which statement is true regarding the execution of the above statement?

OCP 11g 051题库

A. The view will be created and you can perform DML operations on the view.

B. The view will be created but no DML operations will be allowed on the view.

C. The view will not be created because the join statements are not allowed for creating a view.

D. The view will not be created because the GROUP BY clause is not allowed for creating a view.

Answer: B

QUESTION 41

Which two statements are true regarding views? (Choose two.)

A. A subquery that defines a view cannot include the GROUP BY clause.

B. A view that is created with the subquery having the DISTINCT keyword can be updated.

C. A view that is created with the subquery having the pseudo column ROWNUM keyword cannot be updated.

D. A data manipulation language ( DML) operation can be performed on a view that is created with the subquery having all the NOT N

Answer: CD

QUESTION 42

Which three statements are true regarding views? (Choose three.)

A. Views can be created only from tables.

B. Views can be created from tables or other views.

C. Only simple views can use indexes existing on the underlying tables.

D. Both simple and complex views can use indexes existing on the underlying tables.

E. Complex views can be created only on multiple tables that exist in the same schema.

F. Complex views can be created on multiple tables that exist in the same or different schemas.

Answer: BDF

QUESTION 43

Evaluate the following CREATE SEQUENCE statement:

CREATE SEQUENCE seq1

START WITH 100

INCREMENT BY 10

MAXVALUE 200

CYCLE

NOCACHE;

The SEQ1 sequence has generated numbers up to the maximum limit of 200. You issue the following SQL

statement:

SELECT seq1.nextval FROM dual;

What is displayed by the SELECT statement?

A. 1

B. 10

C. 100

D. an error

Answer: A

OCP 11g 051题库

QUESTION 44

View the Exhibit and examine the structure of the ORD table.

Evaluate the following SQL statements that are executed in a user session in the specified order:

CREATE SEQUENCE ord_seq;

SELECT ord_seq.nextval

FROM dual;

INSERT INTO ord

VALUES (ord_seq.CURRVAL, '25-jan-2007',101);

UPDATE ord

SET ord_no= ord_seq.NEXTVAL

WHERE cust_id =101;

What would be the outcome of the above statements?

A. All the statements would execute successfully and the ORD_NO column would contain the value 2 for the CUST_ID 101.

B. The CREATE SEQUENCE command would not execute because the minimum value and maximum value for the sequence have n

C. The CREATE SEQUENCE command would not execute because the starting value of the sequence and the increment value have

D. All the statements would execute successfully and the ORD_NO column would have the value 20 for the CUST_ID 101 because the

20.

Answer: A

QUESTION 45

Which two statements are true about sequences created in a single instance database? (Choose two.)

A. The numbers generated by a sequence can be used only for one table.

B. DELETE <sequencename> would remove a sequence from the database.

C. CURRVAL is used to refer to the last sequence number that has been generated.

D. When the MAXVALUE limit for a sequence is reached, you can increase the MAXVALUE limit by using the ALTER SEQUENCE staE. When a database instance shuts down abnormally, the sequence numbers that have been cached but not used would be available

database instance is restarted.

Answer: CD

QUESTION 46

Which statements are correct regarding indexes? (Choose all that apply.)

A. When a table is dropped, the corresponding indexes are automatically dropped.

B. A FOREIGN KEY constraint on a column in a table automatically creates a nonunique index.

C. A nondeferrable PRIMARY KEY or UNIQUE KEY constraint in a table automatically creates a unique index.

D. For each data manipulation language (DML) operation performed, the corresponding indexes are automatically updated.

OCP 11g 051题库

View the Exhibit and examine the structure of ORD and ORD_ITEMS tables.

The ORD_NO column is PRIMARY KEY in the ORD table and the ORD_NO and ITEM_NO columns are

composite PRIMARY KEY in the ORD_ITEMS table.

Which two CREATE INDEX statements are valid? (Choose two.)

A. CREATE INDEX ord_idx1

ON ord(ord_no);

B. CREATE INDEX ord_idx2

ON ord_items(ord_no);

C. CREATE INDEX ord_idx3

ON ord_items(item_no);

D. CREATE INDEX ord_idx4

ON ord,ord_items(ord_no, ord_date,qty);

Answer: BC

QUESTION 48

Which two statements are true regarding indexes? (Choose two.)

A. They can be created on tables and clusters.

B. They can be created on tables and simple views.

C. You can create only one index by using the same columns.

D. You can create more than one index by using the same columns if you specify distinctly different combinations of the columns.

Answer: AD

QUESTION 49

The ORDERS table belongs to the user OE. OE has granted the SELECT privilege on the ORDERS

table to the user HR.

Which statement would create a synonym ORD so that HR can execute the following query successfully?

SELECT * FROM ord;

A. CREATE SYNONYM ord FOR orders; This command is issued by OE.

B. CREATE PUBLIC SYNONYM ord FOR orders; This command is issued by OE.

C. CREATE SYNONYM ord FOR oe.orders; This command is issued by the database administrator.

D. CREATE PUBLIC SYNONYM ord FOR oe.orders; This command is issued by the database administrator.

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