ANSYS动力学分析的几个入门例子

问题三：三角平台受谐波载荷作用,求结构响应

谐波载荷为作用在平台上面一点的集中力，幅值为10N，频率范围5Hz~70Hz

基本过程： 1、建模 2. 求模态解

3、用模态叠加法作谐分析 4. 观察结果

/PREP7 !建模 ET,1,BEAM189 ET,2,SHELL93 R,1,0.01, , , , , , MP,EX,1,210e9 MP,PRXY,1,0.3 MP,DENS,1,7850

SECTYPE, 1, BEAM, RECT, secA, 0 SECOFFSET, CENT

SECDATA,0.005,0.008,0,0,0,0,0,0,0,0 K, ,-0.5,,, K, ,0.5,,, K, ,,,1, K, ,,1,1, K, ,-0.5,1,, K, ,0.5,1,, K, ,,,0.5, A,4,5,6

LSTR, 1, 5 LSTR, 3, 4 LSTR, 2, 6 LSEL,S,LINE,,4,6

LATT,1,1,1, , 7, ,1 LSEL, , , ,ALL

LESIZE,ALL, , ,10, , , , ,1 LMESH,4,6

TYPE, 2 MSHAPE,0,2D MSHKEY,1 AMESH,1 FINISH

/SOL !为了使用模态叠加法谐分析 ANTYPE,2

MODOPT,LANB,20 !先取结构前20阶模态 MXPAND,20, , ,0

MODOPT,LANB,20,0,0, ,OFF KSEL,S,KP,,1,3

DK,ALL, , , ,0,ALL, , , , , , SOLVE FINISH

!/POST1 !最好事先看一下模态结果 !SET,LIST !以了解模态频率范围 !FINISH

/SOL !模态叠加法谐响应分析 ANTYPE,3 HROPT,MSUP HROUT,ON HROPT,MSUP,20, , HROUT,ON,OFF,0

F,177,FY,-10, !施加10N的力在节点177的负Y方向 HARFRQ,5,70, !载荷的强制频率范围 NSUBST,200, KBC,1 ALPHAD,5, SOLVE FINISH

/POST26 !察看位移响应 FILE,,rfrq NUMVAR,20 NSOL,2,139,U,Y, PLVAR,2 FINISH

问题四：三角平台受一地震谱激励,求应力分布和支反力

基本过程： 1、建模 2、求模态解 3、求谱解 4、扩展模态 5、模态合并 6、观察结果

/PREP7 !建模 ET,1,BEAM189 ET,2,SHELL93 R,1,0.01, , , , , , MP,EX,1,210e9 MP,PRXY,1,0.3 MP,DENS,1,7850

SECTYPE, 1, BEAM, RECT, secA, 0 SECOFFSET, CENT

SECDATA,0.005,0.008,0,0,0,0,0,0,0,0 K, ,-0.5,,, K, ,0.5,,, K, ,,,1, K, ,,1,1, K, ,-0.5,1,, K, ,0.5,1,, K, ,,,0.5, A,4,5,6

LSTR, 1, 5 LSTR, 3, 4 LSTR, 2, 6 LSEL,S,LINE,,4,6

LATT,1,1,1, , 7, ,1

LSEL, , , ,ALL

LESIZE,ALL, , ,10, , , , ,1 LMESH,4,6 TYPE, 2 MSHAPE,0,2D MSHKEY,1 AMESH,1 FINISH

/SOL !取前十阶模态 ANTYPE,2

MODOPT,LANB,10 KSEL,S,KP,,1,3

DK,ALL, , , ,0,ALL, , , , , , SOLVE FINISH

/SOL !谱分析 ANTYPE,8 SPOPT,SPRS,10,1 SVTYP,3

SED,0,1,0, !给出激励方向

FREQ,0.25,1.34,6.73,14.6,28.9,0,0,0,0 !激励谱 SV,0,0.00073,0.00016,0.00034,0.00034,0.00052, SOLVE FINISH

/SOL !扩展模态 ANTYPE,2 EXPASS,1

MXPAND,10,0,0,1,0.001, SOLVE FINISH

/SOL !模态合并 ANTYPE,8 SRSS,0.001,DISP SOLVE

/POST1 !观察结果 SET,LIST /INPUT,,mcom PRRSOL,F FINISH

问题五：三角平台受时程载荷作用,求应力分布和变形过程

基本过程： 1、建模

2. 施加随时间变化载荷，定义载荷步 3、求解

4. 在POST1和POST26中观察结果

/PREP7 !建模 ET,1,BEAM189 ET,2,SHELL93 R,1,0.01, , , , , , MP,EX,1,210e9 MP,PRXY,1,0.3 MP,DENS,1,7850

SECTYPE, 1, BEAM, RECT, secA, 0 SECOFFSET, CENT

SECDATA,0.005,0.008,0,0,0,0,0,0,0,0 K, ,-0.5,,, K, ,0.5,,, K, ,,,1, K, ,,1,1, K, ,-0.5,1,, K, ,0.5,1,, K, ,,,0.5, A,4,5,6

LSTR, 1, 5 LSTR, 3, 4 LSTR, 2, 6 LSEL,S,LINE,,4,6

LATT,1,1,1, , 7, ,1 LSEL, , , ,ALL

LESIZE,ALL, , ,10, , , , ,1 LMESH,4,6 TYPE, 2

MSHAPE,0,2D MSHKEY,1 AMESH,1 FINISH

/SOL ANTYPE,4

TRNOPT,FULL !完全法瞬态分析 KSEL,S,KP,,1,3

DK,ALL, , , ,0,ALL, , , , , , OUTRES,ALL,1

ALPHAD,5,

TIME,2 AUTOTS,1

NSUBST,50, , ,1 KBC,0

SFA,ALL,1,PRES,500

LSWRITE,1, TIME,3 LSWRITE,2, TIME,4

SFA,ALL,1,PRES,150 KBC,1 LSWRITE,3, TIME,5

SFA,ALL,1,PRES, LSWRITE,4,

LSSOLVE,1,4,1, FINISH

/POST26 NSOL,2,177,U,Y,uyy PLVAR,2 FINISH

!α阻尼 定义载荷曲线 !求解 !观察变形随时间的变化 !

MSHAPE,0,2D MSHKEY,1 AMESH,1 FINISH

/SOL ANTYPE,4

TRNOPT,FULL !完全法瞬态分析 KSEL,S,KP,,1,3

DK,ALL, , , ,0,ALL, , , , , , OUTRES,ALL,1

ALPHAD,5,

TIME,2 AUTOTS,1

NSUBST,50, , ,1 KBC,0

SFA,ALL,1,PRES,500

LSWRITE,1, TIME,3 LSWRITE,2, TIME,4

SFA,ALL,1,PRES,150 KBC,1 LSWRITE,3, TIME,5

SFA,ALL,1,PRES, LSWRITE,4,

LSSOLVE,1,4,1, FINISH

/POST26 NSOL,2,177,U,Y,uyy PLVAR,2 FINISH

!α阻尼 定义载荷曲线 !求解 !观察变形随时间的变化 !

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